SOLUTION: Please help me solve this equation: x^3-2012^y=26 x,y=?
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Question 707595
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Please help me solve this equation: x^3-2012^y=26 x,y=?
Answer by
KMST(5328)
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With no other restrictions, there should be an infinity number of (x,y) pairs that are solutions.
If x and y must be non-negative integers, (3,0) is the only solution I see.