SOLUTION: Adult tickets to the school musical are $5 and student tickets are $2. There are 300 seats in the auditorium where the musical is being performed. The goal for ticket sales for one
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Question 70685: Adult tickets to the school musical are $5 and student tickets are $2. There are 300 seats in the auditorium where the musical is being performed. The goal for ticket sales for one performance is at least $900. Make a graph showing the number of each kind of ticket needed to be sold to reach the goal. List three possible solutions.
Is this correct?
y<-x+300
y>-5/3x=300
Thanks Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Adult tickets to the school musical are $5 and student tickets are $2. There are 300 seats in the auditorium where the musical is being performed. The goal for ticket sales for one performance is at least $900. Make a graph showing the number of each kind of ticket needed to be sold to reach the goal. List three possible solutions.
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Is this correct?
y<-x+300; this is correct
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y>-5/3x=300; this seems to wrong
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Here is how I would do it:
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x = no. of $5 tickets
y = no. of $2 tickets
x + y <= 300
y <= 300 - x; the same equation that you had
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5x + 2y >= 900
2y >= 900 - 5x
y >= 900/2 - (5/2)x
y >= 450 - 2.5x
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Plot these two equations:
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The area of feasibility would be at or above the green, at or below the red>
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At the intersection x=100, y = 200; 5(100) + 2(200) = 900
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Note in the triangle to the right of the intersection, the $900 minimum would be
exceeded in that area.
For example: x = 200, y = 100, then: 5(200) + 2(100) = $1200
or x = 250, y = 50, then 5(250) + 2(50) = $1350
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I'm sure you can find a third one in this area
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