SOLUTION: what is the solution of the equation? sqrt(2x+13) -5 = x

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Question 703695: what is the solution of the equation?
sqrt(2x+13) -5 = x

Answer by Nfrey78(18) About Me  (Show Source):
You can put this solution on YOUR website!
what is the solution of the equation?
sqrt%282x%2B13%29+-5+=+x
To solve a radical equation we first need to get the radical, i.e. square root, by itself
Add 5 to both sides to get
sqrt%282x%2B13%29=+x+%2B+5
To "undo" the square root function, we need to do the inverse, which is square both sides. Notice that the square root is now undone
2x%2B13=+%28x+%2B+5%29%5E2
Squaring the right side is the same as (x + 5)(x + 5). Many students often make the mistake of saying it would be x%5E2+%2B+25 forgetting that they need to FOIL this expression out. Done correctly we should get
2x%2B13=+x%5E2+%2B+10x+%2B+25
We can see this results in a quadratic, which means we have to set it to zero, moving everything to one side
0=+x%5E2+%2B+10x+-2x+%2B+25+-+13
Simplifying the right side by combining like terms yields
0=+x%5E2+%2B+8x+%2B+12
After set to zero we factor. What multiplies to give 12 but adds to 8?
0=+%28x+%2B+6%29%28x+%2B+2%29
Set each factor to zero
+x%2B6+=+0 or x+%2B+2=0
and solve for x to get our solutions!
x+=+-6 or x+=+-2