SOLUTION: Write the equation of the line which has y-intercept (0, 5) and is perpendicular to the line with equation y = –3x + 1.
(A) y = – x + 5
(B) y = 3x + 5
(C) y = –3x + 5
(D) y =
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-> SOLUTION: Write the equation of the line which has y-intercept (0, 5) and is perpendicular to the line with equation y = –3x + 1.
(A) y = – x + 5
(B) y = 3x + 5
(C) y = –3x + 5
(D) y =
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Question 69823: Write the equation of the line which has y-intercept (0, 5) and is perpendicular to the line with equation y = –3x + 1.
(A) y = – x + 5
(B) y = 3x + 5
(C) y = –3x + 5
(D) y = x + 5
You can put this solution on YOUR website! Write the equation of the line which has y-intercept (0, 5) and is perpendicular to the line with equation y = –3x + 1
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I don't think any of the answers given are right:
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Find the slope of a line perpendicular to y = -3x + 1; let m2 = -3
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The relationship of the slopes of lines which are perpendicular is:
m1*m2 = -1
m1(-3) = -1; find m1
m1 = -1/-3
m1 = (1/3)
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Use the point/slope equation; y-y1 = m(x-x1) and y intercept coordinates; 0,5
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y - 5 = (1/3)(x - 0
y = (1/3)x + 5
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A graphical presentation:
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