SOLUTION: Please help me with the following..Thank you! Solve for x in {{{a^2(a-x)=(b^2(b+x))-2abx}}} My working...where did I go wrong? {{{a^3-a^2x-b^3-b^2x+2abx=0}}} {{{a^2x-b^2x+2

Algebra ->  Equations -> SOLUTION: Please help me with the following..Thank you! Solve for x in {{{a^2(a-x)=(b^2(b+x))-2abx}}} My working...where did I go wrong? {{{a^3-a^2x-b^3-b^2x+2abx=0}}} {{{a^2x-b^2x+2      Log On


   

Question 696808: Please help me with the following..Thank you!
Solve for x in a%5E2%28a-x%29=%28b%5E2%28b%2Bx%29%29-2abx
My working...where did I go wrong?
a%5E3-a%5E2x-b%5E3-b%5E2x%2B2abx=0
a%5E2x-b%5E2x%2B2abx=b%5E3-a%5E3=x%28a%5E2-b%5E2%2B2ab%29
x=%28b%5E3-a%5E3%29%2F%28a%5E2-b%5E2%2B2ab%29
The correct answer is x=%28a%5E2%2Bab%2Bb%5E2%29%2F%28a-b%29
Answer by god2012(113) About Me  (Show Source):
You can put this solution on YOUR website!
This problem is already solved