SOLUTION: 10[(t+2)]^2]^2-17(t+2)^2+3=0 solve the equation.

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Question 696341: 10[(t+2)]^2]^2-17(t+2)^2+3=0 solve the equation.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
10[(t+2)]^2]^2-17(t+2)^2+3=0 solve the equation.
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Let w = (t+2)^2
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10w^2 - 17w + 3 = 0
Factor:
(2w-3)(5w-1) = 0
w = 3/2 or w = 1/5
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(t+2)^2 = 3/2 or (t+2)^2 = 1/5
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t+2 = sqrt(3/2) or t+2 = -sqrt(3/2) or t+2 sqrt(1/5) or t=2 = -sqrt(1/5)
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etc..
Solve for "t":
Cheers,
Stan H.