SOLUTION: The length of the base of a triangle three times the height. The area of the triangle is 54 squared. Find the base and height of the triangle. (by factoring) Im confused on the

Algebra ->  Equations -> SOLUTION: The length of the base of a triangle three times the height. The area of the triangle is 54 squared. Find the base and height of the triangle. (by factoring) Im confused on the      Log On


   

Question 689286: The length of the base of a triangle three times the height. The area of the triangle is 54 squared. Find the base and height of the triangle. (by factoring)
Im confused on the formula I should be using. Do I need a formula?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
The formula for the area of a triangle would be useful here
A = 1%2F2bh
:
The length of the base of a triangle three times the height.
the equation for this statement:
b = 3h
:
The area of the triangle is 54 squared. Assume you mean 54 sq/units here
1%2F2*b*h = 54
multiply both sides by 2, get rid of the fraction
b*h = 108
Replace b with 3h
3h*h = 108
3h^2 = 108
Divide both sides by 3
h^2 = 36
find the square root of both sides
h = sqrt%2836%29
h = 6 units is the height
then
b = 3h
3(6) = 18 units is base
:
;
Check this
1%2F2*18*6 = 54


Find the base and height of the triangle.
Base = 18, height = 6; (not sure about the factoring requirement)