SOLUTION: Solve the system of equations using the addition method. 2x + 9y = -49 10x + 3y = 49

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Question 689076: Solve the system of equations using the addition method.
2x + 9y = -49
10x + 3y = 49

Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

Solved by pluggable solver: Solving a System of Linear Equations by Elimination/Addition


Lets start with the given system of linear equations

2%2Ax%2B9%2Ay=-49
10%2Ax%2B3%2Ay=49

In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for y, we would have to eliminate x (or vice versa).

So lets eliminate x. In order to do that, we need to have both x coefficients that are equal but have opposite signs (for instance 2 and -2 are equal but have opposite signs). This way they will add to zero.

So to make the x coefficients equal but opposite, we need to multiply both x coefficients by some number to get them to an equal number. So if we wanted to get 2 and 10 to some equal number, we could try to get them to the LCM.

Since the LCM of 2 and 10 is 10, we need to multiply both sides of the top equation by 5 and multiply both sides of the bottom equation by -1 like this:

5%2A%282%2Ax%2B9%2Ay%29=%28-49%29%2A5 Multiply the top equation (both sides) by 5
-1%2A%2810%2Ax%2B3%2Ay%29=%2849%29%2A-1 Multiply the bottom equation (both sides) by -1


So after multiplying we get this:
10%2Ax%2B45%2Ay=-245
-10%2Ax-3%2Ay=-49

Notice how 10 and -10 add to zero (ie 10%2B-10=0)


Now add the equations together. In order to add 2 equations, group like terms and combine them
%2810%2Ax-10%2Ax%29%2B%2845%2Ay-3%2Ay%29=-245-49

%2810-10%29%2Ax%2B%2845-3%29y=-245-49

cross%2810%2B-10%29%2Ax%2B%2845-3%29%2Ay=-245-49 Notice the x coefficients add to zero and cancel out. This means we've eliminated x altogether.



So after adding and canceling out the x terms we're left with:

42%2Ay=-294

y=-294%2F42 Divide both sides by 42 to solve for y



y=-7 Reduce


Now plug this answer into the top equation 2%2Ax%2B9%2Ay=-49 to solve for x

2%2Ax%2B9%28-7%29=-49 Plug in y=-7


2%2Ax-63=-49 Multiply



2%2Ax=-49%2B63 Subtract -63 from both sides

2%2Ax=14 Combine the terms on the right side

cross%28%281%2F2%29%282%29%29%2Ax=%2814%29%281%2F2%29 Multiply both sides by 1%2F2. This will cancel out 2 on the left side.


x=7 Multiply the terms on the right side


So our answer is

x=7, y=-7

which also looks like

(7, -7)

Notice if we graph the equations (if you need help with graphing, check out this solver)

2%2Ax%2B9%2Ay=-49
10%2Ax%2B3%2Ay=49

we get



graph of 2%2Ax%2B9%2Ay=-49 (red) 10%2Ax%2B3%2Ay=49 (green) (hint: you may have to solve for y to graph these) and the intersection of the lines (blue circle).


and we can see that the two equations intersect at (7,-7). This verifies our answer.