SOLUTION: What values for q (0 < q < 2p) satisfy the equation? 2&#8730;2 sin q + 2 = 0

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Question 678264: What values for q (0 < q < 2p) satisfy the equation?
2√2 sin q + 2 = 0
Answer by pmatei(79) About Me  (Show Source):
You can put this solution on YOUR website!
2sqrt%282%29sin%28q%29+%2B+2+=+0
2sqrt%282%29sin%28q%29+=+-2
sin%28q%29+=+-1%2Fsqrt%282%29+=+-sqrt%282%29%2F2
Sine function is negative in quadrants III and IV. sqrt%282%29%2F2 corresponds to an angle of 45 degrees (or pi%2F4) in quadrant I.
Thus q%5BIII%5D+=+5pi%2F4 in quadrant III, and q%5BIV%5D+=+7pi%2F4 in quadrant IV.