SOLUTION: How do you solve this? 4(8-2b)-2b <_32 sign is less than or equal to 32

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Question 674694: How do you solve this?
4(8-2b)-2b <_32
sign is less than or equal to 32
Found 2 solutions by unlockmath, vleith:
Answer by unlockmath(1688) About Me  (Show Source):
You can put this solution on YOUR website!
Hello,
First, let's expand this 4(8-2b)-2b <_32 to:
32-8b-2b <_32
Combine like terms and subtract 32 to get:
-10b<_0
Divide by -10:
b>_0
Make sense?
RJ
www.math-unlock.com

Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
4%288-2b%29-2b+%3C=32 use distribution to expand the left most term
32+-+8b+-+2b+%3C=+32 collect like terms (collect the terms with b in them and also collect the constants)
-10b+%3C=+0 isolate the variable by dividing both sides by -10
b+%3E=+0+ remember that when you divide or multiply an inequality by a negative number, you must flip the sign of the inequality
Test your answer by selecting a value for b that is > 0, one that is 0, and one that is less than 0 . Then verify the result is 'true' for >0 and 0. And hat it is not true for b < 0.