SOLUTION: Express the quadratic in standard form f(x)=3x^2-6x+1

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Question 662176: Express the quadratic in standard form f(x)=3x^2-6x+1
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

the vertex form of a Parabola opening up(a>0) or down(a<0): y=a%28x-h%29%5E2+%2Bk 

where(h,k) is the vertex  and  x = h  is the Line of Symmetry

The standard form is %28x+-h%29%5E2+=+4p%28y+-k%29

f(x)=3x^2-6x +1 = 3%28x-1%29%5E2+-+3+%2B+1+=+3%28x-1%29%5E2+-+2+=+y

 (x-1)^2 = (1/3)(y+2)