SOLUTION: hi there, how do you solve for i in this situation... (i(1+i)^12)/(((1+i)^12)-1)

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Question 661877: hi there, how do you solve for i in this situation... (i(1+i)^12)/(((1+i)^12)-1)
Answer by math-vortex(648) About Me  (Show Source):
You can put this solution on YOUR website!
Hi, there-

Your Question:
Simplify %28i%281%2Bi%29%5E12%29%2F%28%28%281%2Bi%29%5E12%29-1%29

Answer:
The imaginary number i is so much fun to play with! (OK, maybe that's too nerdy)

Remember, 
i=sqrt%28-1%29
i%5E2=-1

So, using exponent laws, we have,
%281%2Bi%29%5E2=%281%2Bi%29%281%2Bi%29=1%2B2i-1=2i
%281%2Bi%29%5E4+=%281%2Bi%29%5E2%281%2Bi%29%5E2=%282i%29%282i%29=%284%29%28-1%29=-4
%281%2Bi%29%5E12=%281%2Bi%29%5E4%281%2Bi%29%5E4%281%2Bi%29%5E4=%28-4%29%28-4%29%28-4%29=-64



~Mrs. Figgy