SOLUTION: The second of two numbers is 6 less than the first. Twice the sum of the first number and 1 is the same as 9 times the second. Find the numbers. i tried to start the equation an

Algebra ->  Equations -> SOLUTION: The second of two numbers is 6 less than the first. Twice the sum of the first number and 1 is the same as 9 times the second. Find the numbers. i tried to start the equation an      Log On


   

Question 660051: The second of two numbers is 6 less than the first. Twice the sum of the first number and 1 is the same as 9 times the second. Find the numbers.
i tried to start the equation and this is what i got but im still not sure:
2(x+1)+x-6=9(x-6)
please help!!!
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
It should be

2(x+1)+x-6=9(x-6)

Notice the change in red

In a much cleaner look, the equation should be this

2(x+1) = 9(x-6)

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2%28x%2B1%29=9%28x-6%29 Start with the given equation.


2x%2B2=9x-54 Distribute.


2x=9x-54-2 Subtract 2 from both sides.


2x-9x=-54-2 Subtract 9x from both sides.


-7x=-54-2 Combine like terms on the left side.


-7x=-56 Combine like terms on the right side.


x=%28-56%29%2F%28-7%29 Divide both sides by -7 to isolate x.


x=8 Reduce.


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Answer:

So the solution is x=8

This means that the first number is 8 and the second number is 2 (since x-6 = 8-6 = 2)

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