SOLUTION: Find all real solutions of equation 2x^2+5x-6=0

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Question 658068: Find all real solutions of equation 2x^2+5x-6=0
Answer by jim_thompson5910(35256) About Me  (Show Source):
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Use the quadratic formula to solve for x

x+=+%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29

x+=+%28-%285%29%2B-sqrt%28%285%29%5E2-4%282%29%28-6%29%29%29%2F%282%282%29%29

x+=+%28-5%2B-sqrt%2825-%28-48%29%29%29%2F%284%29

x+=+%28-5%2B-sqrt%2825%2B48%29%29%2F%284%29

x+=+%28-5%2B-sqrt%2873%29%29%2F4

x+=+%28-5%2Bsqrt%2873%29%29%2F4 or x+=+%28-5-sqrt%2873%29%29%2F4

x+=+0.886000936329383 or x+=+-3.38600093632938

So the exact solutions are x+=+%28-5%2Bsqrt%2873%29%29%2F4 or x+=+%28-5-sqrt%2873%29%29%2F4

and the approximate solutions are x+=+0.886 or x+=+-3.386 (rounded to 3 decimal places)

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