SOLUTION: Find the equation of the line satisfying the given conditions: Passes through the center of the circle (x+2)^2+(y+1)^2=5 and the vertex of the parabola f(x)= -3x^2+12x-10.

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Question 653877: Find the equation of the line satisfying the given conditions: Passes through the center of the circle (x+2)^2+(y+1)^2=5 and the vertex of the parabola f(x)= -3x^2+12x-10.
Answer by solver91311(24713) (Show Source):
You can put this solution on YOUR website!

The equation of a circle centered at with radius is

The vertex of a parabola described as is at the point

Step 1: Rewrite your circle equation:

And then by inspection you can see that the first point for your line is

Step 2: Calculate the -coordinate of your parabola vertex:

Step 3: Evaluate the parabola function at the coordinate of the vertex, i.e. calculate

Step 4: Form an ordered pair from the results of steps 2 and 3.

Step 5: Use the results of steps 1 and 4 and the two-point form of an equation of a line to write your desired equation:

where and are the coordinates of the given points.

John

My calculator said it, I believe it, that settles it