Hi,
x+3y+z=6
3x+y-z=-2
2x+2y-z=1
Basic Plan: ·Use a pair of equations and eliminate one variable.
· Use a different pair of equations and eliminate the same variable.
·Solve the system found, determining the values of those variables.
·Substitute those into an original equation to find the remaining variable’s value.
x+3y+z=6 3x+y-z= -2 || Adding to eliminate z
3x+y-z=-2 2x+2y-z=1 || Subtracting 2nd EQ from 1st to eliminate z
4x + 4y = 4
x - y = -3 ||Multiplying 2nd EQ by 4 and adding to 1st EQ to eliminate y
8x = -8
x = -1 and y = 2
z = 1
and..
