Question 641585: solve the equation in real # system
real solutions of the equation are x=?
dont see why my tutor i was assigned cant do these, please help
Found 2 solutions by Alan3354, MathTherapy:
Answer by Alan3354(69443)   (Show Source):
Answer by MathTherapy(10552)  (Show Source):
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solve the equation in real # system
real solutions of the equation are x=?
dont see why my tutor i was assigned cant do these, please help
 ---- Multiplying eq by 4 to clear the fractions
From calculations,  was found to be a root of the equation.
 -----  ----- 4x + 1 = 0.
This means that one real solution is , or  .
Using long division and dividing  by 4x + 1, we get: 
We now have: ----- 
Solving using the quadratic equation formula gives us a negative discriminant ( ), or 1 – 4 * 1 * 8, or 1 – 32, or - 31)
As a negative discriminant gives us 2 imaginary solutions, both of which DO NOT INTERSECT the x-axis, the 2 imaginary solutions are regarded as non-solutions, since we're looking for real solutions.
Therefore, the one and only REAL solution is  , or  .
I hope this helps you understand it better!!
Send comments and “thank-yous” to “D” at MathMadEzy@aol.com
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