SOLUTION: x^2+(x+2)^2=(x+4)^2 x^2+x^2+4x+4=x^2+8x+16 x^2-4x-12=0 x^2-6x+2x-12=0 x(x-6)+2(x-6)=0 (x-6)(x=2)=o x=6 I solved this problem and I have tried so hard to c

Algebra ->  Equations -> SOLUTION: x^2+(x+2)^2=(x+4)^2 x^2+x^2+4x+4=x^2+8x+16 x^2-4x-12=0 x^2-6x+2x-12=0 x(x-6)+2(x-6)=0 (x-6)(x=2)=o x=6 I solved this problem and I have tried so hard to c      Log On

 

Hi,

x^2-4x-12=0  Good Work!

(x-6)(x + 2)= 0   

 x = 6  0r x = -2

To check: Use EQ given to You and substitute values found

x^2+(x+2)^2=(x+4)^2

   x = 6 checks

      x = -2 checks