SOLUTION: Complete the trinomial so it is a perfect square. x^2 + ___+ 64 Thanks a lot!

Algebra ->  Equations -> SOLUTION: Complete the trinomial so it is a perfect square. x^2 + ___+ 64 Thanks a lot!      Log On


   



Question 632953: Complete the trinomial so it is a perfect square. x^2 + ___+ 64
Thanks a lot!

Found 2 solutions by Edwin McCravy, MathTherapy:
Answer by Edwin McCravy(20055) About Me  (Show Source):
You can put this solution on YOUR website!
x² + ___ + 64

We know it must end up as the square of the sum of the square roots of
the given first and third terms.  The square root of x² is x and the 
square root of 64 is 8. We multiply out the square of their sum, which
is (x+8)²:

 (x+8)² = (x+8)(x+8) = x² + 8x + 8x + 64 = x² + 16x + 64.

So we see now that the middle term has to be the same as that middle term,
which is 16x:

x² + 16x + 64

You can do that or you can memorize the rule.  The middle term is always

TWICE THE PRODUCT OF THE TWO SQUARE ROOTS.

The two square roots are x and 8.  Their product is 8x and twice that is 16x.

The first way is when you can't remember the rule.

Edwin

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
Complete the trinomial so it is a perfect square. x^2 + ___+ 64
Thanks a lot!

Since + 64 (c) is derived from %28b%2F2%29%5E2, then we can say that: %28b%2F2%29%5E2+=+64

b%5E2%2F4+=+64

b%5E2+=+256 ------- Cross-multiplying

b+=+sqrt%28256%29, or 16, making the middle term of the trinomial, highlight_green%2816x%29

The trinomial is therefore: x%5E2+%2B+16x+%2B+64, or %28x+%2B+8%29%5E2

Send comments and “thank-yous” to “D” at MathMadEzy@aol.com