SOLUTION: help! Help! problem 24. using perimeter formula find the perimeter of the rectangle in terms of x. one side is x the other is 3x-8 problem 25. There is an equilateral triangle.

Algebra ->  Equations -> SOLUTION: help! Help! problem 24. using perimeter formula find the perimeter of the rectangle in terms of x. one side is x the other is 3x-8 problem 25. There is an equilateral triangle.       Log On


   



Question 632899: help! Help!
problem 24. using perimeter formula find the perimeter of the rectangle in terms
of x. one side is x the other is 3x-8
problem 25. There is an equilateral triangle. use formula to find its perimeter in terms of x. there is a2x on one side
problem 26. a. persume the perimeters of rectangle in problem 24 and the triangle in problrm 25 are equal,use your answer to 24. and 25 ,find x.
26. B. use answers 24,25,26a calcuate the perimeters of both the rectangle in 24 and the triangle in 25(if calcuations are correct perimeters should be equal)
everything I did is all messed up I am lost,please help me, please

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
The perimeter of any polygon is calculated by adding the lengths of all the sides.

24. Since a rectangle has two pairs of congruent sides, two sides will have a length L, and the other two sides will have a length W, for a perimeter
P=2L%2B2W or highlight%28P=2%28L%2BW%29%29
In this case L%2BW=x%2B3x-8=4x-8 and P=2%284x-8%29 --> highlight%28P=8x-16%29

25. An equilateral triangle has three congruent sides, so if the length of each side is S, the perimeter, P, is
P=3S
If the length of each side is S=2x, the perimeter is
P=3%282x%29 --> P=3%2A2%2Ax --> highlight%28P=6x%29

26.
a. If we presume that the perimeters of the rectangle in problem 24 and the triangle in problem 25 are equal,
8x-16=6x --> 8x-6x-16=6x-6x --> 2x-16=0 --> 2x-16%2B16=0%2B16 --> 2x=16 --> 2x%2F2=16%2F2 --> highlight%28x=8%29
b.Substituting x=8, the perimeter for the rectangle is
P=8x-16 --> P=8%2A8-16 --> P=64-16 --> highlight%28P=48%29
Substituting x=8, the perimeter for the triangle is
P=6x --> P=6%2A8 --> highlight%28P=48%29