SOLUTION: solve y^2+14y=32 by completing the square,..thnks

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Question 632843: solve y^2+14y=32 by completing the square,..thnks
Found 2 solutions by rapaljer, stanbon:
Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
Take HALF of the coefficient of y, which is 7, and SQUARE it to get 49. Add this to each side of the equation:

y^2 + 14y + 49 = 32 + 49
(y+7)^2 = 81

Take the square root of each side:
%28y%2B7%29+=+0+%2B-+9
y=-7+%2B-+9

Calculate each value:
y=-7 +9 =2

y=-7-9 = -16

Dr. Robert J. Rapalje, Retired
Seminole State College of Florida

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
solve y^2+14y=32 by completing the square,..thnks
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y^2 + 14y + (14/2)^2 = 32 + (14/2)^2
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y^2 + 14y + 49 = 81
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(y+7)^2 = 81
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y+7 = 9 or y+7 = -9
y = 2 or y = -16
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Cheers,
Stan H.
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