SOLUTION: If my equation is 3 + the square root of 3a+3 =9, how would I provide the check after I have the equation solved? The square part throws me off when I go to write out the check.

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Question 632645: If my equation is 3 + the square root of 3a+3 =9, how would I provide the check after I have the equation solved? The square part throws me off when I go to write out the check.
Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
3 + sqrt%283a%2B3%29 = 9

Isolate the term with a radical by subtracting 3 from both sides:

    sqrt%283a%2B3%29 = 6

Square both sides. Remember that squaring a square root 
takes away both the radical and the 2 exponent: 

 [sqrt%283a%2B3%29}² = 6²
       3a + 3 = 36
           3a = 33
            a = 11

To check, substitute 11 for a in the original:

3 + sqrt%283a%2B3%29 = 9
3 + sqrt%283%2811%29%2B3%29 = 9
3 + sqrt%2833%2B3%29 = 9
3 + sqrt%2836%29 = 9
3 + 6 = 9
    9 = 9

Edwin