SOLUTION: (x+2)^2+28=0 solve using square root procedure

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Question 617762: (x+2)^2+28=0 solve using square root procedure
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
(x+2)^2+28=0 solve using square root procedure
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(x+2)^2 = -28
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x+2 = +/-2isqrt(7)
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x = -2 + 2isqrt(7) or x = -2 - 2isqrt(7)
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Cheers,
Stan H.
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