SOLUTION: The function below shows the height, in feet, above the ground of a model rocket t seconds after it is launched off a platform.
h(t)= -16t^2+128t+5
How high off the ground do
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-> SOLUTION: The function below shows the height, in feet, above the ground of a model rocket t seconds after it is launched off a platform.
h(t)= -16t^2+128t+5
How high off the ground do
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Question 617046: The function below shows the height, in feet, above the ground of a model rocket t seconds after it is launched off a platform.
h(t)= -16t^2+128t+5
How high off the ground does the rocket start?
When does the rocket reach its highest point?
How high is that?
How long does the rocket stay in the air? Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! The function below shows the height, in feet, above the ground of a model rocket t seconds after it is launched off a platform.
h(t)= -16t^2+128t+5
..
How high off the ground does the rocket start?
5 ft, when t=0
..
When does the rocket reach its highest point?
complete the square:
h(t)=-16(t^2-8t+16)+5+256
h(t)=-16(t-4)^2+261
rocket reach its highest point after 4sec
..
How high is that? 261 ft
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