SOLUTION: f(x)= x^-2x+8\x+4

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Question 61023: f(x)= x^-2x+8\x+4
Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
f(x)=(x^2-2x+8)/(x+4)
You didn't give us instructions.
x cannot = -4 has to be stipulated, because the original function is undefined when it's denominator equals 0
The domain therefore is {x|x cannot=-4}<--set builder notation
There is a vertical asymptote at x=-4
The degree of the numerator is higher than the denominator, so there is no horizontal asymptote.
The degree of the numerator is exactly 1 more than the denominator, so there is a slant asymtote you can get through long division of y=x-6.
If you plot a few points on both sides of x=-4 you get this graph.
graph%28300%2C200%2C-10%2C10%2C-50%2C10%2C%28x%5E2-2x%2B8%29%2F%28x%2B4%29%29
If you had something else in mind, let me know.
Happy Calculating!!!