SOLUTION: please solve for t 8t/(t^2+3)=2

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Question 607249: please solve for t
8t/(t^2+3)=2
Found 2 solutions by stanbon, MathLover1:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
solve for t
8t/(t^2+3)=2
-----
2t^2+6 = 8t
---
t^2-4t+3 = 0
Factor:
(t-3)(t-1) = 0
t = 3 or t = 1
====================
Cheers,
Stan H.
==================

Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
8t%2F%28t%5E2%2B3%29=2.....both sides multiply by t%5E2%2B3
%288t%2F%28t%5E2%2B3%29%29%28t%5E2%2B3%29=2%28t%5E2%2B3%29
%288t%2Fcross%28%28t%5E2%2B3%29%29%29cross%28%28t%5E2%2B3%29%29=2%28t%5E2%2B3%29
8t=2t%5E2%2B6
8t-8t=2t%5E2-8t%2B6
0=2t%5E2-8t%2B6.......or.....2t%5E2-8t%2B6=0.....solve for t using quadratic formula
t+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+...note that a=2, b=-8 and c=6
t+=+%28-%28-8%29+%2B-+sqrt%28%28-8%29%5E2-4%2A2%2A6+%29%29%2F%282%2A2%29+
t+=+%288+%2B-+sqrt%2864-48+%29%29%2F4+
t+=+%288+%2B-+sqrt%2816%29%29%2F4+
t+=+%288+%2B-+4%29%2F4+
solutions:
t+=+%288+%2B4%29%2F4+
t+=+12%2F4+
t+=+3+
or
t+=+%288+-4%29%2F4+
t+=+4%2F4+
t+=+1+