SOLUTION: x2 + y2 = 4 x2 + y = 40 The numbers after the 'x' and 'y' are supposed to be integers.Please can you work out this simultaneous equation . thanks

Algebra ->  Equations -> SOLUTION: x2 + y2 = 4 x2 + y = 40 The numbers after the 'x' and 'y' are supposed to be integers.Please can you work out this simultaneous equation . thanks      Log On


   

Question 602806: x2 + y2 = 4
x2 + y = 40
The numbers after the 'x' and 'y' are supposed to be integers.Please can you work out this simultaneous equation . thanks
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
x2 + y2 = 4
x2 + y = 40
------------ Subtract
y^2 - y = -36
y%5E2+-+y+%2B+36+=+0
y+=+1%2F2+%2B-+i%2Asqrt%28143%29%2F2
------------
x%5E2+=+40+-+y+=+39.5+%2B-+i%2Asqrt%28143%29%2F2
x+=+sqrt%2839.5+%2B-+i%2Asqrt%28143%29%2F2%29
-------------
If you graph these, you'll see a circle and a parabola, and no intersections.
--> no real solutions.
Further manipulation is possible, but I'm not gonna do a lot of work and then have you say you made a typo.