SOLUTION: 1. If X^2+x+1=0 ,then what is the value of (x^3+1/x^3)^3 ?
2. If X^X+Y=Y^3 and Y^X+Y=X^6*Y^3 ,where X and Y are natural numbers then what is the value of Y^X ?
Algebra ->
Equations
-> SOLUTION: 1. If X^2+x+1=0 ,then what is the value of (x^3+1/x^3)^3 ?
2. If X^X+Y=Y^3 and Y^X+Y=X^6*Y^3 ,where X and Y are natural numbers then what is the value of Y^X ?
Log On
Question 596132: 1. If X^2+x+1=0 ,then what is the value of (x^3+1/x^3)^3 ?
2. If X^X+Y=Y^3 and Y^X+Y=X^6*Y^3 ,where X and Y are natural numbers then what is the value of Y^X ?
I already answered 1
http://www.algebra.com/algebra/homework/equations/Equations.faq.question.596131.html
2. If X^X+Y=Y^3 and Y^X+Y=X^6*Y^3 ,where X and Y are natural numbers then what
is the value of Y^X ?
There are no natural number solutions to that, so I assumed you must
have left off the necessary parentheses to show where the exponents start and
end. So I rewrote it as this, which does have 2 natural number solutions:
2. If X^(X+Y)=Y^3 and Y^(X+Y)=X^6*Y^3 ,where X and Y are natural numbers then
what is the value of Y^X ?
or in superscripted exponent notation:
2. If = and = ,where X and
Y are natural numbers then what is the value of Y^X ?
There are two solutions to that (x,y) = (1,1) and (x,y) = (2,4)
So for the first solution = = 1
And for the second = = 16
Edwin