SOLUTION: Solve simultaneously I dont understand..\ y=x^2-4x-2 y=x-2

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Question 595883: Solve simultaneously I dont understand..\
y=x^2-4x-2
y=x-2
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
If y=x^2-4x-2 and y = x-2, then we can say


x - 2 = x^2-4x-2


This is because the two are both simultaneously equal to y. So they must be equal to each other.

From here, solve for x


x+-+2+=+x%5E2-4x-2

0+=+x%5E2-4x-2+-+x+%2B2

0+=+x%5E2-5x

x%5E2-5x+=+0

x%28x-5%29+=+0

x=0 or x-5+=+0

x=0 or x=5

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If x = 0, then y = x-2 = 0-2 = -2

So if x = 0 then y = -2

So one ordered pair solution is (0, -2)


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If x = 5, then y = x-2 = 5-2 = 3

So when x = 5, the value of y is y = 3

So another ordered pair solution is (5, 3)