Question 595557: I need help in writing an equation for this word problem.
Jasper collects nickels,dimes, and quarters in a jar. There are twice as many nickels as there are quarters. If there is $15.30 in dimes and $74.80 in all, how many quarters are there?
This is what I tried: 2x for nickels and x for quarters = 2x + x + $15.30 = $74.80
Answer by llorton(14)   (Show Source):
You can put this solution on YOUR website! Since our values are stated in dollars we will use the decimal equivalents for the quarters (0.25$) and nickels (0.05$), If you don't like working with decimals, you can leave everything at the "penny" level as it allows you to work with integer numbers. Your equation is a good start, but it fails to include the dollar values for a nickel and a quarter.
The value of x quarters is 0.25*x
The value of 2x nickels is 0.05*2*x
The value of the dimes is $15.30.
If we add all that up, the total dollar amount is $74.80.
So your equation would be:
0.25x + 0.05*(2x) + 15.30 = 74.80.
Since you only asked for the equation. I will let you go through the process of solving it. I can tell you that the correct answers are 170 quarters and 340 nickels.
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