SOLUTION: I really need help setting this problem up. I can't figure it out!
Problem:
The perimeter of a rectangle is 20 feet. The width is 4 feet less than the length. Find the dim
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-> SOLUTION: I really need help setting this problem up. I can't figure it out!
Problem:
The perimeter of a rectangle is 20 feet. The width is 4 feet less than the length. Find the dim
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Question 581838: I really need help setting this problem up. I can't figure it out!
Problem:
The perimeter of a rectangle is 20 feet. The width is 4 feet less than the length. Find the dimensions of the rectangle. Then find the area. Answer by smaraya(8) (Show Source):
You can put this solution on YOUR website! let length be x
Let width be x-4
P=perimeter
P=2(l+b)
20=2(x+x-4)
20=2x+2x-8
20+8=4x
x=7
Length is 7 ft
Width is 3 ft
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