SOLUTION: (1 1/2) squared = 1.2 + 1/4
(2 1/2) squared = 2.3 + 1/4
(3 1/2) squared = 3.4 + 1/4
Those are all correct statements. Show algebraically that this method can always be used for
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-> SOLUTION: (1 1/2) squared = 1.2 + 1/4
(2 1/2) squared = 2.3 + 1/4
(3 1/2) squared = 3.4 + 1/4
Those are all correct statements. Show algebraically that this method can always be used for
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Question 578016: (1 1/2) squared = 1.2 + 1/4
(2 1/2) squared = 2.3 + 1/4
(3 1/2) squared = 3.4 + 1/4
Those are all correct statements. Show algebraically that this method can always be used for evaluating similar squares.
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None of those statements are true, there is an error in the problem
(1 1/2)^2 = 2.25 ≠ 1.2 + 1/4 = 1.2 + .25 = 1.45
(2 1/2)^2 = 6.25 ≠ 2.3 + 1/4 =2.55