SOLUTION: a=b+3(4-c) b=5 c=2 what is a ,i need to know how the process is done to get the value of a another question i have is how to solve y=3(x+5)(x-2) i dont remeber the steps involv

Algebra ->  Equations -> SOLUTION: a=b+3(4-c) b=5 c=2 what is a ,i need to know how the process is done to get the value of a another question i have is how to solve y=3(x+5)(x-2) i dont remeber the steps involv      Log On


   

Question 577034: a=b+3(4-c) b=5 c=2 what is a ,i need to know how the process is done to get the value of a
another question i have is how to solve y=3(x+5)(x-2) i dont remeber the steps involved in solving these equations if you could assist me it would be greatly appreciated
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
a=b+3(4-c)

a=5+3(4-2)

a=5+3(2)

a=5+6

a=11

So the answer is a = 11
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I'm assuming you want to find the zeros of y=3(x+5)(x-2)

y=3(x+5)(x-2)

0=3(x+5)(x-2)

3(x+5)(x-2)=0

x+5=0 or x-2=0

x = -5 or x = 2


So the solutions are x = -5 or x = 2