SOLUTION: Find the equation of the line perpendicular to 2x+3y=12 and passes thru the point (-4,6)

Algebra ->  Equations -> SOLUTION: Find the equation of the line perpendicular to 2x+3y=12 and passes thru the point (-4,6)      Log On


   



Question 576464: Find the equation of the line perpendicular to 2x+3y=12 and passes thru the point (-4,6)
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


Since in the given equation the and terms are on the same side of the equals sign, take the opposite of the coefficent on and divide by the coefficient on to find the slope of the line represented by the given equation.

Use the point-slope form of an equation of a line to write the desired equation:



where are the coordinates of the given point and is the calculated slope.

Put the derived equation into either Standard or Slope-Intercept Form as desired by your teacher/professor/instructor.0

However, please note that you cannot write "the" equation of any line. You can only write "an" equation of a line. In the first place, you could just substitute the values in the point-slope form and have an equation of the desired line, or you could solve for to put it into slope-intercept form, or you could rearrange it into standard form, namely . Furthermore, for a given , , and , where describes a set of equations with an infinite number of elements, each of which graphs to the same line in .

John

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