SOLUTION: 5(x-4)=12 solve for X please 12(x-6)=2(x-9) 4(2x-3)+8(x-4)=2(2x+6) 12(2x-8)=4(5-2x)+3(7-3x) 7(2x+6)=1

Algebra ->  Equations -> SOLUTION: 5(x-4)=12 solve for X please 12(x-6)=2(x-9) 4(2x-3)+8(x-4)=2(2x+6) 12(2x-8)=4(5-2x)+3(7-3x) 7(2x+6)=1      Log On


   



Question 575731: 5(x-4)=12 solve for X please
12(x-6)=2(x-9)
4(2x-3)+8(x-4)=2(2x+6)
12(2x-8)=4(5-2x)+3(7-3x)
7(2x+6)=1

Answer by JBarnum(2146) About Me  (Show Source):
You can put this solution on YOUR website!
all these are basically the same order of operations distribution adding multiplication subtraction and division, going with the expextation if you are doing this type of math you know how to multiply divide add and subtract
im only going to do the first one and the longest one so you can see them worked out you should be able to do the rest
.
.
5%28x-4%29=12 theres two different ways to solve this it depends if you like fractions or not.
one way is to divide by 5 firs
x-4=12%2F5
x=%2812%2F5%29%2B4 FYI4+=+20%2F5
x=%2812%2B20%29%2F5
x=32%2F5
or the other is to distribute the 5 first
5x-20=12
5x=32
x=32%2F5
.
.
12%282x-8%29=4%285-2x%29%2B3%287-3x%29 best to just distribute first
24x-96=20-8x%2B21-9x add like terms
24x-96=41-17x add 17x to each side and add 96 to each sides
24x%2B17x=41%2B96
41x=137 divide by 41
x=137%2F41