SOLUTION: For the equation 3x^2+xy+2y^2=0, which of the following is true? (a) x=y+√y^2-4(3)(2y^2) (over/divided)2(3) (b) x=-y+√y^2-4(3)(2y^2) (over/divided)2(3) (c) x=-

Algebra ->  Equations -> SOLUTION: For the equation 3x^2+xy+2y^2=0, which of the following is true? (a) x=y+√y^2-4(3)(2y^2) (over/divided)2(3) (b) x=-y+√y^2-4(3)(2y^2) (over/divided)2(3) (c) x=-      Log On


   

Question 568618: For the equation 3x^2+xy+2y^2=0, which of the following is true?
(a) x=y+√y^2-4(3)(2y^2) (over/divided)2(3)
(b) x=-y+√y^2-4(3)(2y^2) (over/divided)2(3)
(c) x=-y+√x^2-4(3)(2y^2) (over/divided)2(3)
(d) x=-y+√y^2-4(3)(3x^2) (over/divided)2(3)
Thank you so much in advance!
Answer by AnlytcPhil(1806) About Me  (Show Source):
You can put this solution on YOUR website!
3x² + xy + 2y² = 0

(3)x² + (y)x + (2y²) = 0

a=3, b=y, c = 2y²

x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+

x+=+%28-y+%2B-+sqrt%28+y%5E2-4%2A3%2A2y%5E2+%29%29%2F%282%2A3%29+

The 2 solutions are 

x+=+%28-y+%2B+sqrt%28+y%5E2-4%2A3%2A2y%5E2+%29%29%2F%282%2A3%29+ and x+=+%28-y+-+sqrt%28+y%5E2-4%2A3%2A2y%5E2+%29%29%2F%282%2A3%29+

The first one is the same as choice (b)

Edwin