SOLUTION: use the factor theorem to show that x-c is a factor of P(x) for the given values of c and factor P(x) completely.
P(x)=x^3-5x^2+8x-4, c=1
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-> SOLUTION: use the factor theorem to show that x-c is a factor of P(x) for the given values of c and factor P(x) completely.
P(x)=x^3-5x^2+8x-4, c=1
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Question 565167: use the factor theorem to show that x-c is a factor of P(x) for the given values of c and factor P(x) completely.
P(x)=x^3-5x^2+8x-4, c=1 Answer by ad_alta(240) (Show Source):
You can put this solution on YOUR website! I'm not sure which factor theorem you're referring to, but it's easy to use polynomial division to do the same thing. You should come up with a factorization of (x-2)^2(x-1).
