You can put this solution on YOUR website! 8x^3 - 18x factor completely.
Find the common factor: 2x
Factor it out of each of the terms:
=2x(4x^2-9)
4x^2-9 is the "difference of two squares
and it is factorable:
=2x(2x-3)(2x+3)
These factors cannot be further simplified.
Cheers,
Stan H.
You can put this solution on YOUR website! 8x^3 - 18x
Both term have the same factor ...
8x^3 --> 2*2*2*x*x*x
18x --> 2*3*3*x
==> 2*x (the common factor)...
2x{4x^2-9}
Then the 4x^2-9 can be written in this form {2x}^2-{3}^2 --> {2x+3}{2x-3}
Therefore
8x^3 - 18x = 2x{4x^2-9}= 2x{2x+3}{2x-3}
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