SOLUTION: Identify whether the parabola y=-(x-3)^2 +6 opens up or down and identify the vertex, x-intercepts and y-intercepts. I know it opens down but, I am not sure how to identify the i
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Question 56387: Identify whether the parabola y=-(x-3)^2 +6 opens up or down and identify the vertex, x-intercepts and y-intercepts. I know it opens down but, I am not sure how to identify the intercepts or vertex (3,6)? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! y=-(x-3)^2 +6
Intercepts:
Let x=0 to get the y-intercept:
y=-9+6=-3; y-intercept is (0.3)
Let y=0 to get the x-intercepts:
0=-(x-3)^2+6
(x-3)^2=6
x-3=+-sqrt6
x=3+sqrt6 or x=3-sqrt6
These are the x intercepts.
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Vertex:
(x-3)^2=-(y-6)
Vertex at (3,6)
Cheers,
Stan H.
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