SOLUTION: the question asks to solve: 5t^2-27t+22=0 could t=1 and t=4.4 ??

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Question 561375: the question asks to solve: 5t^2-27t+22=0
could t=1 and t=4.4
??
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

5t%5E2-27t%2B22=0 Start with the given equation.


Notice that the quadratic 5t%5E2-27t%2B22 is in the form of At%5E2%2BBt%2BC where A=5, B=-27, and C=22


Let's use the quadratic formula to solve for "t":


t+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29 Start with the quadratic formula


t+=+%28-%28-27%29+%2B-+sqrt%28+%28-27%29%5E2-4%285%29%2822%29+%29%29%2F%282%285%29%29 Plug in A=5, B=-27, and C=22


t+=+%2827+%2B-+sqrt%28+%28-27%29%5E2-4%285%29%2822%29+%29%29%2F%282%285%29%29 Negate -27 to get 27.


t+=+%2827+%2B-+sqrt%28+729-4%285%29%2822%29+%29%29%2F%282%285%29%29 Square -27 to get 729.


t+=+%2827+%2B-+sqrt%28+729-440+%29%29%2F%282%285%29%29 Multiply 4%285%29%2822%29 to get 440


t+=+%2827+%2B-+sqrt%28+289+%29%29%2F%282%285%29%29 Subtract 440 from 729 to get 289


t+=+%2827+%2B-+sqrt%28+289+%29%29%2F%2810%29 Multiply 2 and 5 to get 10.


t+=+%2827+%2B-+17%29%2F%2810%29 Take the square root of 289 to get 17.


t+=+%2827+%2B+17%29%2F%2810%29 or t+=+%2827+-+17%29%2F%2810%29 Break up the expression.


t+=+%2844%29%2F%2810%29 or t+=++%2810%29%2F%2810%29 Combine like terms.


t+=+22%2F5 or t+=+1 Simplify.


So the solutions are t+=+22%2F5 or t+=+1


Note: 22/5 = 4.4


So you have the correct answers.
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