SOLUTION: (sin^2theta+cos^2theta-3)^4=
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Question 551013
:
(sin^2theta+cos^2theta-3)^4=
Answer by
Alan3354(69443)
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(sin^2theta+cos^2theta-3)^4=
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Is it cos^2(theta - 3) ?
or cos^2(theta) - 3 ?
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=
= 16