SOLUTION: Find the equation of the line perpendicular to -4x-8y=-5 that contains the point (-2,5).
a.y=1/2x+6
b.y=2x+1
c.y=-2x+1
d.y=2x+9
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-> SOLUTION: Find the equation of the line perpendicular to -4x-8y=-5 that contains the point (-2,5).
a.y=1/2x+6
b.y=2x+1
c.y=-2x+1
d.y=2x+9
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Question 549875: Find the equation of the line perpendicular to -4x-8y=-5 that contains the point (-2,5).
a.y=1/2x+6
b.y=2x+1
c.y=-2x+1
d.y=2x+9 Answer by nyc_function(2741) (Show Source):
The slope of -4x-8y = -5 is 1/2. The line that you are searching for must have a slope that when multiplied by 1/2 will yield -1. So, 1/2 times what number yields -1? How about -2? Yes, 1/2 times -2 = -1. The equation you need has a slope of -2. Do you think you can find the answer now?