SOLUTION: {{{7x/(x-3) - 21/x + 11 = 63/(x^2-3x)}}}

Algebra ->  Equations -> SOLUTION: {{{7x/(x-3) - 21/x + 11 = 63/(x^2-3x)}}}      Log On


   



Question 549458: 7x%2F%28x-3%29+-+21%2Fx+%2B+11+=+63%2F%28x%5E2-3x%29
Answer by mathie123(224) About Me  (Show Source):
You can put this solution on YOUR website!
7x%2F%28x-3%29+-+21%2Fx+%2B+11+=+63%2F%28x%5E2-3x%29

let's first see if we can factor any numerator or denominators
we can see that x%5E2-3x=x%28x-3%29 so we now have:
7x%2F%28x-3%29+-+21%2Fx+%2B+11+=+63%2F%28x%28x-3%29%29
I don't know about you... but I do not like working with fractions... let's get rid of them. We notice that the first two denominators multiply together to give the third denominator. So we can multiply each term by x(x-3) giving us:

%28x%29%2A%287x%29+-%28x-3%29%2A%2821%29+%2B+%28x%28x-3%29%29%2A11+=+%2863%29
%287x%5E2%29+-%2821%2Ax-63%29+%2B+%28x%5E2-3x%29%2A11+=+63
7x%5E2-21%2Ax%2B63%2B11%2Ax%5E2-33%2Ax+=+63

Now we collect like terms:
63%2B18%2Ax%5E2-54%2Ax+=+63
And move everything to one side to leave us with the form ax^2+b+c=0
18%2Ax%5E2-54%2Ax+=0
We can see that we can do some common factoring to leave us:
18%2Ax%28x-3%29+=0

So if we have two things together to give a product of 0, then at least one of them must be 0 This means either:
18x=0
x=0
or
x-3=0
x=3

Hopefully this helps!
Have a good one!