SOLUTION: Jamie can solve 2 equations in a minute. Mackey can solve 3 equations in a minute. Jamie starts working at 10 A.M. and Mackey starts working at noon. What time will Mackey have sol

Algebra ->  Equations -> SOLUTION: Jamie can solve 2 equations in a minute. Mackey can solve 3 equations in a minute. Jamie starts working at 10 A.M. and Mackey starts working at noon. What time will Mackey have sol      Log On


   



Question 544844: Jamie can solve 2 equations in a minute. Mackey can solve 3 equations in a minute. Jamie starts working at 10 A.M. and Mackey starts working at noon. What time will Mackey have solved as many problems as Jamie?
Found 2 solutions by ankor@dixie-net.com, josmiceli:
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Jamie can solve 2 equations in a minute. Mackey can solve 3 equations in a minute.
Jamie starts working at 10 A.M. and Mackey starts working at noon.
What time will Mackey have solved as many problems as Jamie?
:
Let m = no. of minutes worked by Mackey (who started at noon)
then
(m + 120) = no. of minutes worked by Jamie
:
3m = 2(m + 120)
3m = 2m + 240
3m - 2m = 240
m = 240 minutes which is 4 hrs
:
They will have worked the same number equations at 4 PM

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The key is to find out how many equations Jamie
solves before Mackey starts solving
--------
Jamie's rate of solving is ( 2 equations) / ( 1 minute )
Mackey's rate of solving is ( 3 equations / 1 minute )
--------
Jamie's head start is:
( rate ) x ( time ) = +%282%2F1%29%2A120+ ( there are 120 minutes in 2 hrs )
+%282%2F1%29%2A120+=+240+ equations
--------
Let x = number of problems that mackey solves
until they both solve the same number of equations
Let t = time until they both have solved the
same number of equations
--------
Start a stopwatch when Mackey starts solving
Jamie's equation:
(1) +x+-+240+=+2t+
Mackey's equation:
(2) +x+=+3t+
--------
Substitute )2) into (1)
(1) +3t+-+240+=+2t+
(1) +t+=+240+ minutes
+240%2F60+=+4+ hours
They will both have solved the same number of
equations at noon + 4 hrs, or 4 PM