SOLUTION: This is for anyone familiar with the FOIL Method. I have to find the product of:
(2y - 5)(y - 2) using the FOIL Method.
What I have so far is:
2y^2 - 2y -5y + 10
10 + -2
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-> SOLUTION: This is for anyone familiar with the FOIL Method. I have to find the product of:
(2y - 5)(y - 2) using the FOIL Method.
What I have so far is:
2y^2 - 2y -5y + 10
10 + -2
Log On
Question 54233: This is for anyone familiar with the FOIL Method. I have to find the product of:
(2y - 5)(y - 2) using the FOIL Method.
What I have so far is:
2y^2 - 2y -5y + 10
10 + -2y + -5y + 2y^2
-2y + -5y = -7y
10 + -7y + 2y^2
Is this in any way correct? Answer by Cintchr(481) (Show Source):
You can put this solution on YOUR website! You miscalculated ...
(2y - 5)(y - 2)
F: 2y * y = 2y^2
O: 2y * -2 = -4y
I: -5 * y = -5y
L: -5 * -2 = -10
Add the O and I
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