SOLUTION: This is the last one that I am struggling with. 2r-2/ r^2+3r-28 + 4/r+7 = r/r-4 This should read 2r-2 over r squared plus 3r minus 28 plus 4 over r+7 equals 1 over r-4.

Algebra ->  Equations -> SOLUTION: This is the last one that I am struggling with. 2r-2/ r^2+3r-28 + 4/r+7 = r/r-4 This should read 2r-2 over r squared plus 3r minus 28 plus 4 over r+7 equals 1 over r-4.      Log On


   

Question 540745: This is the last one that I am struggling with.
2r-2/ r^2+3r-28 + 4/r+7 = r/r-4
This should read 2r-2 over r squared plus 3r minus 28 plus 4 over r+7 equals 1 over r-4.
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!

I am assuming the last fraction is 1/(r-4) as you said in the text
:
%28%282r-2%29%29%2F%28%28r%5E2%2B3r-28%29%29 + 4%2F%28%28r%2B7%29%29 = 1%2F%28%28r-4%29%29
Factor the 1st denominator and this will all make sense
%28%282r-2%29%29%2F%28%28r%2B7%29%28r-4%29%29 + 4%2F%28%28r%2B7%29%29 = 1%2F%28%28r-4%29%29
Multiply by (r+7)(r-4), cancels the denominators and you have
2r - 2 + 4(r-4) = r + 7
2r - 2 + 4r - 16 = r + 7
6r - 18 = r + 7
6r - r = 7 + 18
5r = 25
r = 25/5
r = 5
You can check this solution in the original equation