SOLUTION: the sum of the ages of tony and teddy equals thrice their mother's age. tony is two years younger than teddy. if the age of the mother is 42, find their ages of tony and teddy

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Question 536340: the sum of the ages of tony and teddy equals thrice their mother's age. tony is two years younger than teddy. if the age of the mother is 42, find their ages of tony and teddy
Found 2 solutions by mananth, MathTherapy:
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
Tony + teddy = 42
Tony = 42-Teddy
Let tony be x
Teddy = 42-x
Teddy = Tony +2
42-x=x+2
42-2=2x
40=2x
/2
x=20 Tony's age
Teddy's age = 22
m.ananth@hotmail.ca

Answer by MathTherapy(10551) About Me  (Show Source):
You can put this solution on YOUR website!
the sum of the ages of tony and teddy equals thrice their mother's age. tony is two years younger than teddy. if the age of the mother is 42, find their ages of tony and teddy

I think the problem meant to say: the sum of Tony's and Teddy's ages is 1/3 their mother's age, or, thrice the sum of Teddy's and Tony's ages equals their mother's age. If I were to set this up just as it's stated, it'd result in Teddy being 62 years-old, which doesn't make any sense since their mother's 42.

With that said, let Teddy’s age be T
Then Tony’s age = T – 2

We can then say that: 3(T + T – 2) = 42

3(2T – 2) = 42

6T – 6 = 42

6T = 48

T, or Teddy’s age = 48%2F6, or highlight_green%288%29

This means that Tony is highlight_green%286%29 (8 – 2) years-old

I'll leave the check up to you!!

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