Question 53633: Complete the ordered pairs so the each is a solution for the given equation.
3x + 4y = 12 (0, ), ( ,3/4), ( ,0), (8/3, ). Thanks so much for youer help!!! Mcgraw Hill 6th edition, chapter 6, section 1, prolem # 24.
Found 3 solutions by rchill, funmath, AnlytcPhil:
Answer by rchill(405)   (Show Source):
You can put this solution on YOUR website! First, solve the equation for y by subtracting 3x from both sides and then dividing both sides by 4 to get  . Next, solve the original equation for x by subtracting 4y from both sides and dividing by 3 to get  .
Now all you need to do is substitute in the values of your ordered pairs to solve for either x or y, whichever is missing from the ordered pair. For example, for ordered pair (0, ), we know x=0, so solve for y by substitution in the first equation above to get  . That means the ordered pair is (0,3). For the next ordered pair ( ,3/4) we know  , so substitute that into the 2nd equation above to get  . That means the ordered pair is (3,3/4).
Now that you know how to do it, you can find the other two ordered pairs!
Answer by funmath(2933) (Show Source):
You can put this solution on YOUR website! Ordered pairs are given as (x,y).
For (0,y), let x=0 and solve for y.
3x+4y=12
3(0)+4y=12
4y=12
4y/4=12/4
y=3
Your ordered pair is: (0,3)
----------------------------
for (x,3/4)
Let y=3/4 and solve for x.
3x+4(3/4)=12
3x+12/4=12
3x+3=12
3x+3-3=12-3
3x=9
3x/3=9/3
x=3
Your ordered pair is: (3,3/4)
-----------------------------
for (x,0)
Let y=0 and solve for x.
3x+4(0)=12
3x=12
3x/3=12/3
x=4
Your ordered pair is: (4,0)
-----------------------------
for (8/3,y)
let x=8/3 and solve for y.
3(8/3)+4y=12
24/3+4y=12
8+4y=12
-8+8+4y=12-8
4y=4
4y/4=4/4
y=1
Your ordered pair is: (8/3,1)
Happy Calculating!
Answer by AnlytcPhil(1806)  (Show Source):
You can put this solution on YOUR website! Complete the ordered pairs so the each is a solution for the given equation.
3x + 4y = 12 (0, ), ( ,3/4), ( ,0), (8/3, ).
------------------------------
In an ordered pair the x-xoordinate is first and the y-coordinate is second.
If you are given the first coordinate and are asked to find the second one,
substitute the first coordinate for x in the equation and solve for y, and
put that in for the missing second coordinate.
If you are given the second coordinate and are asked to find the first one,
substitute the second coordinate for y in the equation and solve for x, and
put that in for the missing first coordinate.
------------------------------------
3x + 4y = 12 (0, )
Here we are given the first coordinate, 0, and are asked to find the
second one, so we substitute 0 for x in the equation and solve for y:
3(0) + 4y = 12
0 + 4y = 12
4y = 12
y = 12/4
y = 3
and we put 3 in for the missing second coordinate and get (0, 3)
----------------------
3x + 4y = 12 ( , 3/4)
Here we are given the second coordinate, 3/4, and are asked to find the
first one, so we substitute 3/4 for y in the equation and solve for x:
3x + 4(3/4) = 12
3x + 3 = 12
-3 -3
-----------------
3x = 9
x = 9/3
x = 3
and we put 3 in for the missing first coordinate and get (3, 3/4)
----------------------
3x + 4y = 12 ( , 0)
Here we are given the second coordinate, 0, and are asked to find the
first one, so we substitute 0 for y in the equation and solve for x:
3x + 4(0) = 12
3x + 0 = 12
3x = 12
x = 12/3
x = 4
and we put 4 in for the missing first coordinate and get (4, 0)
------------------------------------
3x + 4y = 12 (8/3, )
Here we are given the first coordinate, 8/3, and are asked to find the
second one, so we substitute 8/3 for x in the equation and solve for y:
3(8/3) + 4y = 12
8 + 4y = 12
-8 -8
-----------------
4y = 4
y = 4/4
y = 1
and we put 1 in for the missing second coordinate and get (8/3, 1)
Edwin
|
|
|
