SOLUTION: Write the equation of a line, in slope-intercept form, that is perpendicular to: -8x + 3y + 7 = -6
I really need help in solving this.
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I really need help in solving this.
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Question 536199: Write the equation of a line, in slope-intercept form, that is perpendicular to: -8x + 3y + 7 = -6
I really need help in solving this. Found 2 solutions by richwmiller, oberobic:Answer by richwmiller(17219) (Show Source):
You can put this solution on YOUR website! -8x + 3y +7 = -6
-8x + 3y = -13
3y = 8x -13
y = 8/3*x -13/3
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When x=0, y=-13/3
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When y = 0,
-8/3*x = -13/3
cross multiply
-8x*3 = 3*-13
-24x = -39
x = 39/24 = 13/8
so
x = 13/8, y =0
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The equation of the line perpendicular to y = 8/3*x -13/3 will have the slope = to the inverse reciprocal of the 8/3, which = -3/8.
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y = -3/8x
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This line does not have to go through any specific point, so you can leave it there.
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