SOLUTION: I give up!!! Please help. The perimeter of a rectangle is to be no greater than 300 in. and the length must be 125 in. Find the maximum width of the rectangle.

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Question 53270: I give up!!! Please help.
The perimeter of a rectangle is to be no greater than 300 in. and the length must be 125 in. Find the maximum width of the rectangle.
Found 2 solutions by Nate, ankor@dixie-net.com:
Answer by Nate(3500) (Show Source):
You can put this solution on YOUR website!
Perimeter = 2l + 2w

Measurements can not be negative. Also, if the width was zero, you would not have a shape at all.

Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website!
Don't give up!!
:
The perimeter of a rectangle is to be no greater than 300 and the length must be 125 in. Find the maximum width of the rectangle.
:
Remember the perimeter equation:
2L + 2W = P
:
You know the length and the perimeter Substitute for L & P:
2(125) + 2W =< 300
:
250 + 2W =< 300
:
2W =< 300 - 250
:
2W =< 50
:
W =< 50/2
:
W =< 25